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Use the quadratic equation y = x^2 + 3x – 10. Calculate the discriminant to determine the number of real roots.
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A. one real root B. two real roots C. no real roots D. no solution to the equation
the discriminant is b^2 -4ac, in your equation b=3, a=1 and c=-10 If the discriminant is positive, you have two real roots, if it is negative, you have no real roots, if it is zero, then you have only one solution
so... the answer is c
not c. keep i'm mind the negatives
well, when i do b^2 -4ac i get (3)^2-4(1)(-10)=49
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so the answer should be B, two real roots
OK THANKS
Your are welcome :)
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