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Mathematics 19 Online
OpenStudy (anonymous):

What is the value of x, given that PQ is parallel to BC?

OpenStudy (anonymous):

OpenStudy (anonymous):

@Nurali

OpenStudy (mayankdevnani):

@Emily778 do you know what is Thales Theorem???

OpenStudy (anonymous):

NO

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (mayankdevnani):

thales theorem states that \[\huge \frac{AP}{PB}=\frac{AQ}{QC}\]

OpenStudy (mayankdevnani):

where AP=8,PB=32,AQ=x and QC=36.

jimthompson5910 (jim_thompson5910):

the two triangles are similar, so you can say 8/(32+8) = x/(36+x) solve for x

OpenStudy (mayankdevnani):

can you solve it @Emily778

OpenStudy (anonymous):

8 x 32?

OpenStudy (mayankdevnani):

\[\huge \frac{8}{32}=\frac{x}{36}\] Can you solve for x???

OpenStudy (anonymous):

.25

OpenStudy (anonymous):

or..Do I cross multiply?

OpenStudy (mayankdevnani):

yeah!!

jimthompson5910 (jim_thompson5910):

8/(32+8) = x/(36+x) 8/40 = x/(36+x) 8(36+x) = 40x ... ... ... x = ??

OpenStudy (anonymous):

288

OpenStudy (mayankdevnani):

what x=288????

OpenStudy (anonymous):

x=18?

OpenStudy (mayankdevnani):

no, wrong

OpenStudy (anonymous):

9?

OpenStudy (mayankdevnani):

correct

ganeshie8 (ganeshie8):

left side you see, 8 is 4 times lees than 32 so right side, 9 has to 4 times less than 36. 9 works.

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