Question

16 < 3x + 1 < 4
Part 1: Solve the inequality above.
Part 2: Describe the graph of the solution.

Answer 1

no such thing

Answer 2

\[16<whatever <4\] implies \(16<4\) which is false
there is no solution

Answer 3

okay so how did you come up with 16<4. I have to explain every step

Answer 4

this
16 < 3x + 1 < 4

means
16 < 3x +1 and
3x + 1 < 4

you can simplify them:
16 < 3x + 1 add -1 to both sides:
16+ -1 < 3x + 1 + -1 (the 1 + -1 is 0 and 3x+0 is 3x, so you get:
15 < 3x
divide both sides by 3:
15/3 < 3x/3
5 < x

we can do the same for the other relation:
3x+1 < 4 becomes 3x < 3 and then x < 3

so you need
x > 5 (x bigger than 5) and
x < 3 (at the same time, x less than 3)

which is not possible.