16

Question

16 < 3x + 1 < 4
Part 1: Solve the inequality above.
Part 2: Describe the graph of the solution.

anonymous · Answer

no such thing

anonymous · Answer

$$16<whatever <4$$ implies $16<4$ which is false
there is no solution

anonymous · Answer

okay so how did you come up with 16<4. I have to explain every step

phi · Answer

this
16 < 3x + 1 < 4

means
16 < 3x +1     and
3x + 1 < 4

you can simplify them:   
16 < 3x + 1     add -1 to both sides:
16+ -1 < 3x + 1 + -1   (the 1 + -1 is 0  and 3x+0 is 3x, so you get:
15 < 3x
divide both sides by 3:
15/3 < 3x/3  
5 < x

we can do the same for the other relation:
3x+1 < 4  becomes   3x < 3    and then x < 3

so you need 
x > 5   (x bigger than 5) and
x < 3  (at the same time, x less than 3)

which is not possible.