Find the constant of variation if y varies inversely as x, and y = 15 when x = 5.
Assume that y varies inversely as x. Find x when y= 6 if y = 4.2 when x = 10.
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OpenStudy (anonymous):
Help! :O
geerky42 (geerky42):
"y varies inversely as x"
So it's y = k/x where k is an unknown constant. You need to find k.
geerky42 (geerky42):
Let's do the first one.\[y = \dfrac{k}{x}\Rightarrow 15 = \dfrac{k}{5}\]
geerky42 (geerky42):
Can you find the value of k?
OpenStudy (anonymous):
hmm
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OpenStudy (anonymous):
How do I find it
OpenStudy (anonymous):
3?
geerky42 (geerky42):
All you have to do is to isolate k. So we have to do something with 5 in denominator.
OpenStudy (anonymous):
Ohh
OpenStudy (anonymous):
15 * 5? or 15/5
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geerky42 (geerky42):
15*5
geerky42 (geerky42):
because you can remove 5 in denominator by multiplying both sides by 5.
OpenStudy (anonymous):
75
OpenStudy (anonymous):
??
@geerky42
geerky42 (geerky42):
Yes.
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OpenStudy (anonymous):
So the answer for that one is 75
geerky42 (geerky42):
Yes. 75 is the constant of variation.
OpenStudy (anonymous):
Now this one 'Assume that y varies inversely as x. Find x when y= 6 if y = 4.2 when x = 10.
geerky42 (geerky42):
This time, it take a little more work. First you need to find k again. Can you do it this time by yourself?
OpenStudy (anonymous):
I will try
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OpenStudy (anonymous):
When x=5, y=15 so x/y=1/3 so if y=5 then x/5=1/3 so x=5/3.