Question

Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than the square of the largest number. @tcarroll010

Answer 1

Hey shortie! The best thing to do in a problem like this would be to do this: \[x + (x+1) + (x+2)=64\] then you would take \[(x + x + 1)^2\] and then you would find the square of the larger number. Try it out, and tell me what you get.