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Mathematics 13 Online
OpenStudy (anonymous):

x^2+x-20=0

OpenStudy (luigi0210):

are we solving?

OpenStudy (anonymous):

It factors to (x-5) (x+4) so the solutions are 5 and -4.

OpenStudy (luigi0210):

If so, what you could you could factor it into: (x+5)(x-4), they multiply to -20 and add up to a positive 1

OpenStudy (anonymous):

Given the equation x2 - x - 20 = 0, we see that it can likely be factored easily. Through simple trial and error we find that: (x - 5)(x + 4) = 0. From here, we set both terms equal to zero to find all possible solutions. x - 5 = 0 x = 5 and x + 4 = 0 x = -4. Substituting 5 and -4 back into the original equation yield true results. Thus the solution set is x = -4, 5. More formal, the solution set is {-4, 5}. Note: There are other methods of solving this problem such as the quadratic formula or by graphing the function.

OpenStudy (anonymous):

understood?

OpenStudy (luigi0210):

that's x^2+x-20 alli :P

OpenStudy (anonymous):

lol... :P

OpenStudy (luigi0210):

Haha, well your work can not go unrewarded

OpenStudy (anonymous):

k bye hahhaha ;)

OpenStudy (luigi0210):

Thank you Miss Alli, I will catch you later

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