Question

3. A force F = (4, -7, 3), in Newtons, pulls a sled through a displacement s = (5, -6, -1) in metres. How much work is done on the sled by the force?

Answer 1

work done = force * displacemant

Answer 2

so multiply the two vectors: F * s

Answer 3

so just (4, -7, 3)*(5, -6, -1) -- no weird square rooting or anything?

Answer 4

wait its a while since i did mechanics - let me check that out

Answer 5

okay :)

Answer 6

ok

the work done = scalar or dot product of the vectors

which is

4*5 + -7*-6 + 3*-1