write the equation of the line that contains (1,4) and (3,10) in point slope, slope intercept, and standard form
find slope y2 - y1 ------ = m x2-x1 point slope y - y1 = m(x - x1) you put in the y1, the x1 and the m
x1 y1 x2 y2 ( 1, 4) (3, 10)
We can write : \[y=ax+b\] where : \[a=\frac{y_2-y_1}{x_2-x_1}=\frac{10-4}{3-1}=3\] For finding b, because (1,4) is from the line, we have : \[4=1\times a+b=3+b\] so : \[b=4-3=1\] Hence , the equation is : \[y=3x+1\]
Whats the m, is it the slope?
and for the point slope does it matter which set of variables you use
if you mean, does it matter which points you use? no you can use either one
cool beans
how do I turn this into standard form?
start with y = 3x +1 now get the 1 by itself
now the trick with standard from is that the x's go first and they have to be positive what did you do to get the 1 by itself?
or are you still working on the point slope?
you good here?
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