Question

Another inequality...these bad boys are lethal, need help!



Solve the inequality x + 8<5 or -8x<16

Answer 1

1st equation subtract 8 from both sides
2nd equation divide both sides by -8 and flip the inequality

Answer 2

ok and what would the interval notation look like

Answer 3

(-infnity,-3)U(-2,infinity)

Answer 4

hmm i was sure it was -3,-2 but ight thanks for the help:)

Answer 5

Solve both for \(x\) and *combine.*

$$x+8<5\\x+8-8<5-8\\x<-3\\x\in(-\infty,-3)$$and$$-8x<16\\\frac{-8x}{-8}>\frac{16}{-8}\\x>-2\\x\in(-2,\infty)$$hence \(x\in(-\infty,-3)\cap(-2,\infty)=\emptyset\) or, equivalently, \(-2<x<-3\) which no real number satisfies...

Answer 6

no this is not right

Answer 7

or!

Answer 8

or not and

Answer 9

(-infnity,-3)U(-2,infinity) not (-infnity,-3)n(-2,infinity)

Answer 10

it just means x needs to satisfy one equation not both @oldrin.bataku

Answer 11

@zzr0ck3r trust me I know that. I misread 'or' as 'and'. It would correctly be \(x\in(-\infty,-3)\cup(-2,\infty)\)

Answer 12

right, that's why I told you:) I assume you would know it....