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Statistics 21 Online
OpenStudy (anonymous):

In USA Today (Sept. 5, 1996) the results of a survey involving the use of sleepwear while traveling were listed as follows: Male Female Underwear 0.220 0.024 0.244 Nightgown 0.002 0.180 0.182 Nothing 0.160 0.018 0.178 Pajamas 0.102 0.073 0.175 T-shirt 0.046 0.088 0.134 Other 0.084 0.003 0.087 (a) What is the probability that a traveler is a female who sleeps in the nude? (b) What is the probability that a traveler is male? (c) Assuming the traveler is male, what is the probability that he sleeps in pajamas? (d) What is the probability that a traveler

OpenStudy (texaschic101):

you have a male and a female category, but you have 3 number categories. Is there something besides male and female such as both ?

OpenStudy (anonymous):

the third one is TOTAL. plzz help

OpenStudy (texaschic101):

(a) female, nude is 0.18/0.178 reduces to .09/.089 (b) I am not sure about this one...I know you put the total number of males over the total number of people. I am thinking you add the males that sleep in underwear, nightgowns,nothing,pajamas etc. and you put that over the "totals" category added together. (c) male,pajamas is 0.102/0.175 (d) question is not finished.

OpenStudy (anonymous):

sorry about that (d) What is the probability that a traveler is male if he sleeps in pajamas or a t-shirt

OpenStudy (texaschic101):

(d) 0.102/0.175 * 0.046/0.134 = .004692/.02345 (I think) You might want to get a second opinion on these.....they are not my best subject.

OpenStudy (anonymous):

OR indicates addition.NO?

OpenStudy (texaschic101):

sorry...I am not sure....you might want to tag someone who might know this stuff better then me.

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