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A ball is thrown vertically upward with a speed of 26 m/s. What is its velocity when it returns to the level from which it started? Answer in units of m/s.
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I assumed the velocity should be the same, (so the answer would be 26 m/s) but that's not the case. Is there an equation I'm supposed to use??
All right calculate the distance travelled upwards using v^2-u^2=2gh.Tke g=- and v=0,and then equate it with the same eqn in downward direction.i think u=v i.e it will come out to be same 26 m/s.are you sure it's not the case?
Yeah, it keeps saying I'm wrong so it has to be the software being incorrect. Thanks though, glad to know I was doing it right:)
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