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Evaluate the Intergal
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\[\int\limits_{}^{}Tan ^{5}(\theta)\sec^5(\theta) d \theta \]
I feel like I am missing something obvious. I factored out a sec^2(x) and used the Trig identity tan^2(x) = sec^2(x)-1 but it's not working >.< .
Those should say theta not x sorry :P .
That is incorrect. I just solved it.
Thanks anyways :) .
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\[\frac{ \sec^3(\theta) }{ 3 }-\frac{ 2\sec^5(\theta) }{ 5 }+\frac{ \sec^7(\theta) }{ 7 } +C\]
i haven't finished solving it but it seems like if u let u=sec(x) you will be fine.
No no, I got it thanks a lot though :) .
And you are absolutely correct.
good work :)
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