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How do you figure out the centripetal component of a acceleration vector when given only the acceleration vector and the unit normal vector?
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Recall that acceleration can be decomposed into a centripetal component in the direction of the normal vector and a tangential component in the direction of the tangent vector. This means acceleration lies in the plane spanned by the tangent and normal vectors, lets call them \(\mathbf{T},\mathbf{N}\):|dw:1370838638203:dw|
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