Question

1. x – 3 > –9

2. –2x + 1 ≤ –11

3. 10 < –3x + 1

4. 2(x + 5) > 8x – 8

5. –2(x – 3) ≥ 5 – (x + 3)
Im having problems especially with 4 and 5. Can someone help me and show me the steps?

Answer 1

4. Start by distributing the 2 through the parentheses. Can you do that?

Answer 2

Um. Would i add the 2 on each sides?

Answer 3

Forget this problem now. You need to review the distributive property.
The distributive property is
a(b + c) = ab + ac
Example: 2(5 + 6) = 2*5 + 2*6 = 10 + 12 = 22

Answer 4

To use the distributive property, you multiply the number outside the parentheses by each number inside the parentheses.

Answer 5

Now let's get back to your problem.

Answer 6

I dont have time to review. I have to get 5 other assignments done by today. And this is part of one. I just dont get how to solve inequalities.

Answer 7

4. Start by distributing the 2 through the parentheses.
2(x + 5) > 8x – 8
Using the distributive property on the left side, you get
2x + 2*5 > 8x - 8
2x + 10 > 8x - 8

Answer 8

Ok, now subtract 8x from both sides.

Answer 9

-6x + 10 > -8
Now subtract 10 from both sides:
-6x > -18
Now you need to divide both sides by -6 to get x. In an inequiality, when you multiply or divide both sides by a negative number, the inequality sign changes direction:
x < 3
Final answer.

Answer 10

Okay. I think i get it now. So would 1. be x > -6

Answer 11

And would 2. be x ≥ 6?

Answer 12

1 and 2 are correct

Answer 13

How about 3.
First add 3x to both sides to bring the x term to the left side.

Answer 14

Then subtract 10 from both sides.

Answer 15

-9 > x?

Answer 16

3. First add 3x to both sides to bring the x term to the left side.
10 < –3x +
Subtract 10 from both sides:
3x + 10 < 1
3x < -9
Now divide both sides by 3