Question

Inverse functions?

The functions are:
sin^-1(.65)
tan^-1(-.09)

I have to put them in radians

Answer 1

Where is the function ?

Answer 2

@Noura11 i just edited the question

Answer 3

In this case you should use the calculator !
\[\sin^{-1}(0.65)=0.707\text{ rd}\]

Answer 4

my options are these:

http://puu.sh/3cR2l.png

that's why i got confused

Answer 5

and these are the options for \[\tan^{-1} (-.09)\]

http://puu.sh/3cR9Q.png

Answer 6

Yes !
In general case : to find
\[\sin^{-1}(\alpha)=\beta +2k\pi\text{ or } (\pi-\beta)+2k\pi~~k\in{\mathbb Z}\]
where
\[\beta\]
is the number that we will get by using the calculator

Answer 7

okay, the answer i got from the calculator was like you said, .707 or .71.

so it'd be .71 + 2kpi?

Answer 8

The answer should be like this :
\[\sin^{-1}(0.65)=.71+2k\pi \text{ or } (\pi-.71)+2k\pi\]

Answer 9

but there is no option for 2kpi. would it be the same as 2pi n?

Answer 10

Yes ! k or n ! There is no difference !

Answer 11

okay, and the one for tan^-1(-.09) is option a?

Answer 12

NO !
It is tha last one !
Because we have :
\[\tan^{-1}(\alpha)=\beta +n\pi\]
where
\[\beta\]
is the number that we will get by using the calculator !