2|2x -1| + 5 = 15
1) subtract 5 2) divide by 2
\[2|2x-1|+5=15\]\[2|2x-1|=10\]\[|2x-1|=5\]So, 2x - 1 have to be equal to -5 or 5. \[2x-1=5 <=> x = 3\]\[2x-1=-5 <=> x=-2\] Solutions: x = -2 and x = 5
@zairhenrique try \iff
\(\iff\)
Oh, thanks :]
yw i wonder whatever happened to the group "latex practice"? it was very useful
I2x-1I=5
I've recently started using latex, so, i don't know a lot of expressions. Next time I will google it.
best thing to do is if you see something you like, right click and view the code
@FutureMathProfessor please help
@jazzyfa30 where you are having troubles?
I thought when when you have absolute value symbols then it is answer is positive
No, |2x-1| have to be 5. So 2x - 1 can be -5 or 5, because |-5| = 5 and |5| = 5. So, 2x - 1 = -5 , x = -2 and 2x -1 = 5, x = 3
In my first solutions in the end i've writed solutions: x = -2 and x = 5, it's incorrect, it's x = -2 and x = 3.
wait so how did you get x=-2 from 2x-1=-5
2x - 1 = -5 2x = -5 + 1 2x = -4 x = -2
oh okay thank you
you welcome :]
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