Find the interval of concavity and the inflection point(s) for g(x)=x^4-8x^2-9 = (x-3)(x+3) [x^2+1] ?

Question

jhannybean · Answer

intervals of concavity can be found by taking the second derivative of the function.

jhannybean · Answer

Same with inflection points

dan815 · Answer

interval of concavity is the distance in x between points where the graph switches from convex to concave, and viceversa

anonymous · Answer

I'm just stuck because the second derivative is g''(x)=-24[3^2+6x+7]/(x+3)^3(x-1)^3 and I don't know how to begin to find it

anonymous · Answer

like I understand what it is and what I have to look for i'm just having troubles starting is what i'm saying

dan815 · Answer

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