Question

What is the equation of the circle graphed below?

Answer 1

The circle is centered at a=0, b=0 and has a radius of z=2

The equation for a circle is \[(x-a)^{2}+(y-b)^{2} = z^{2}\ (Circle\ Equation)\]

By substituting the a,b and z values in the circle equation, you can find the equation
for this case.

Answer 2

(x-0)^2 +(y-0) =2

Answer 3

like that?

Answer 4

\[(x-0)^2 + (y-0)^2 = 2^2\]

Answer 5

thanks