Question

I need help quick I am so confused...
Part 1:
Solve each of the quadratic equations below and describe what the solution(s) represent to the graph of each. Show your work to receive full credit.
•0 = x2 + 5x + 6
•0 = x2 + 4x + 4
Part 2:
Using complete sentences, answer the following questions about the two quadratic equations above.•Do the two quadratic equations have anything in common? If so, what?
•What makes y = x2 + 4x + 4 different from y = x2 + 5x + 6?

Answer 1

Take first equation first.
you start by recognizing the values of \(a,b,c\) in order to use the formula with the \(\Delta\) (discriminant). that, you must do.

Answer 2

So in the first equation A=1,B=5, and C=6

Answer 3

yes. I'll not recall anything from it. Go as far as you can, and write again when you're stuck.

Answer 4

What is the formula you were talking about because we do it differently?

Answer 5

ah do your method. what's the name of that method of yours?

Answer 6

We use factoring

Answer 7

can you write the steps? I suppose it's not long.

Answer 8

0=x^2+5x+6
1.Now you must find a set of numbers that when multiplied gives you 6 and when the same two numbers are added give you 5.

Answer 9

Oh that ok ok.

Answer 10

Yeahh unfortunately that

Answer 11

thinking about the product equal to 6 is better than looking for the sum equal to 5 (more possibilities).

Answer 12

Okay I did part 1 now I need help w/part 2

Answer 13

part 2, first (•) is a bit general. It could be a lot of things. But they have a common root.

Answer 14

Is there common root 2?

Answer 15

it's -2. (because \((x+2)=0\) iff \(x=-2\).)

Answer 16

Ohh true

Answer 17

for the second (•), you have to look at the roots again. And just state something that makes both sets of roots different. What do you think of?

Answer 18

The x values in the first equation are the same and in the second equation they aren't?

Answer 19

if you mean "-2 and -2 are equal, not -2 and -3", you're right. that's all they want to hear from you. —i think.

Answer 20

Okay thanks:)

Answer 21

yw

Answer 22

there are only 3 possibilites for solutions with quadratics
case 1: 2 solutions (the function crosses in 2 places on the x axis)
case 2: 1 solution (function crosses in 1 place on the x axis)
case 3: 2 complex solutions or aka as no solution (the function does not cross the x axis at all)

Answer 23

Thanks:)