Question

3 = log8 + 3logx

Answer 1

adding the logs of two numbers is like taking the log of the product of the two numbers. \[\log a+\log b = \log (a*b)\]

Multiplying the log of a number is like taking the log of the number to that power.
\[a \log b = \log b^a\]

With those two rules, can you rewrite your equation into a form where we might find the value of \(x\)?

Answer 2

Did you close the question because you have solved it, or did you give up?