Question

help, please.

Let f(x) = 2x2 – 2x + 7 and g(x) = x2 + 9x – 6. Find f(x) – g(x).

x2 – 11x + 13

x2 – 11x + 1

x2 + 7x + 1

x2 + 7x + 13

Answer 1

f(x) – g(x) = (2x^2 – 2x + 7) - (x^2 + 9x – 6)

f(x) – g(x) = 2x^2 – 2x + 7 - x^2 - 9x + 6

f(x) – g(x) = ???

Answer 2

C?

Answer 3

2x^2 - x^2 is what

Answer 4

this is the part where you jump in dreamer05 (don't worry if you're wrong)

Answer 5

f(x)-g(x) = (2x2 -2x + 7) - (x2 + 9x - 6)
= (2x2 - x2) + (-2x - 9x) + (7 + 6)
= x2 - ... (do you see it?)

Answer 6

Well i was thinking. 3x^2 but I know thats wrong..

Answer 7

2x^2 -x^2 is really the same as 2x^2 - 1x^2

Answer 8

So x^2
?

Answer 9

to combine 2x^2 - 1x^2 you subtract the coefficients

so....

2-1 = 1

which means

2x^2 - 1x^2 = 1x^2 or just x^2

Answer 10

correct

Answer 11

So its not C?

Answer 12

for the x terms

-2x - 9x = -11x

because -2 - 9 = -11 (all you focus on are the coefficients)

Answer 13

B? Makes since to me.

Answer 14

you have to look at the whole picture

Answer 15

the constants are 7 and 6, they add to ???

Answer 16

13

Answer 17

so to sum things up

f(x) – g(x) = (2x^2 – 2x + 7) - (x^2 + 9x – 6)

f(x) – g(x) = 2x^2 – 2x + 7 - x^2 - 9x + 6

f(x) – g(x) = (2x^2 - 1x^2) + (-2x - 9x) + (7 + 6)

f(x) – g(x) = (1x^2) + (-11x) + (13)

f(x) – g(x) = x^2 - 11x + 13

Answer 18

Okay I seee. Thank you.

Answer 19

yw