Question

x³-3x²-2=0 factorize please?

Answer 1

x^3 - 3x^2 -2 = 0

(x^3 + 1) + (-3x^2 + 3) do you see what I have done here?
just pulled them apart creating
a sum of 2 cubes in the 1st

Answer 2

(x^3 + 1) + (-3x^2 + 3)

(x+ 1)(x^2 -x + 1) +(-3x^2 + 3) sum of 2 cubes

Answer 3

(x^3 + 1) + (-3x^2 + 3)

(x+ 1)(x^2 -x + 1) +(-3x^2 + 3) sum of 2 cubes

(x+ 1)(x^2 -x + 1) -3(x^2 - 1) factor out the -3

you with me?

Answer 4

owh okk @Jim766 thanks !!!

Answer 5

(x^3 + 1) + (-3x^2 + 3)

(x+ 1)(x^2 -x + 1) +(-3x^2 + 3) sum of 2 cubes

(x+ 1)(x^2 -x + 1) -3(x^2 - 1) factor out the -3

(x+1)(x^2-x+1) -3(x+ 1)(x -1)= 0 difference of 2 squares

Answer 6

(x+1)(x^2-x+1) -3(x+ 1)(x -1)= 0 difference of 2 squares

(x+1) [(x^2 -x+ 1) -3(x-1)] factor out the (x+1)

(x+1)(x^2-x+1 -3x + 3)

you still with me?

Answer 7

ya @Jim766 getting it in my head... thanks tho..:)

Answer 8

(x+1)(x^2-x+1 -3x + 3) = 0

(x+1)(x^2 -4x + 4) = 0

(x + 2)(x -2)^2 = 0

(x + 1)( x - 2)(x - 2) = 0

x + 1= 0 , x -2 = 0

solutions are -1 and 2