multiply or divide 5x+10/x+2*2x/4x-10
@skullpatrol
@e.cociuba
@ganeshie8 @amistre64
its quite simple really 5(x+2)/(x+2)x 2x/2(x-2) x+2 and 2 cancel 5x/(x-2) is answer
how does x+2 and 2 cancel?
(5x+10)/(x+2)*(2x)/(4x-10) (5(x)+5(2))/(x+2)*(2x)/(4x-10) (5(x+2))/(x+2)*(2x)/(4x-10) (5 (x+2) )/( (x+2) )*(2x)/(4x-10) 5*(2x)/(4x-10) 5*(2x)/(2(2x)+2(-5)) 5*(2x)/(2(2x-5)) 5*(x)/(2x-5) (5x)/(2x-5) is the answer.
I did it the longer way, but @ArslanQureshi u can take this one :))
no x+2 and x+2 in the first term and 2 and 2 in the second one and @e.cociuba you can have one from me for your hard work :)
Haha thanks :)
thnx guys i really apreciate it. i have another question
ask :)
3n^2-n/n^2-1 divided by n^2/n+1
3n^2-n/n^2-1 / n^2/n+1 n(3n-1)/n^2-1 x n+1/n^2 (3n-1)/(n+1)(n-1) x(n+1)/n---- n in the first term gets cancelled with n^2 leaving n n(3n-1)/(n-1) is your answer ---- (n+1)s cancel
so the answwer would be 3n?
no the term in the last line is the answer n(3n-1)/(n-1)
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