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x^12 z^11 / x^2 z^4 Is the simplified version 1/x^10 z^7 ? @jim_thompson5910
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You would do well to utilize the following: a^b / a^c = a^(b-c)
Was I incorrect?
Yes. So, you would subtract 2 from the 12 and keep "x" on top and subtract 4 from the 11 and keep "z" on top. There will be no denominator when you are done.
Oh! Thanks!
uw! Good luck in all of your studies and thx for the recognition! @unheard
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