Question

Which Is equivalent to the expression?

Answer 1

Maybe c, I'm not sure

Answer 2

to add them, their denominators must bet he same.

you need to cross multiply to achieve this. this uses the other term's denominator. notice we are basically multiplying by one:

\[\frac{ z+3 }{ z-2 } - \frac{ 2+z }{ z-3 } = \frac{ z+3 }{ z-2 }\frac{ z-3}{ z-3 } - \frac{ 2+z }{ z-3 } \frac{ z-2 }{ z-2 }\]

= \[\frac{ (z+3)(z-3) - (2+z)(z-2) }{ (z-2)(z-3) } = \frac{ (z^2 - 9) - (z^2 - 4)}{ z^2 -5z + 6 } = \frac{ -5}{ z^2 -5z + 6 }\]

Answer 3

Thank u evry one :D