Question

solve by factoring 6t^2+t-5=0

Answer 1

(6t-5)( + )

that will give you a good start

Answer 2

When there's a constant outside the x^2 terms (or t^2) in this case... a good trick is to multiply the constants of the 1st and last term, and think of which two factors, when added, give the constant of the middle term.

Here: 6*-5 = -30
conatnat of middle term +t is 1

so -30 = 6*(-5), and 6+(-5) =1

So... we write it it as 6t^2 + 6t - 5t -5 = 0

Then it's clear how to factor this.

Answer 3

Seeing it that way is analogous to factoring when you don't have a coefficient in front of x^2

Answer 4

\[6 t^2+t-5=(t+1) (6 t-5) \]