I am missing something simple. How do I find the y-intercept of the tangent line to y=(1.2)/(3+7x)^-1/2 at (3,0.245)
well, i assume you've found the point it is tangent, yes?
then just create a formula for a line by y = mx + b where m is the slope, and (x,y) is the point it is tangent then solve for b and there ya go!
Thanks and should I derive thos equation, plug in (3) for X to find m?
yes, the derivative of the equation at the point (3,.0245) will tell you the slope
using the given point, the slope you're about to find, you can then solve for b using y = mx + b
I am having an issue solving for x in this equation.
you don't need to solve for x
to find the slope at the tangent point 1. take the derivative 2. plug in known (x,y) values 3. the answer is the slope
Thanks.....I knew I was missing something simple.
and you don't have to plug in the y value, by the way just the x value my bad
you'll be left with something like dy/dx = "number" that number being the slope :)
i've gotta leave, so to re-cap: 1. find derivative 2. plug in x value 3. you'll be left with something like dy/dx = slope 4. using the given (x,y) point, and the slope you just found 5. plug them into y = mx+b and find b
good luck mate
1.derive the equation 2.plug in x 3.the answer is the slope 4.plug the slope, y and x to solve for b 5. let x=0 to find the y-intercept
Thanks
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