Part 1: Make up an angle measure for angle C and a length for one of the sides (AB, BC, or CA). Part 2: Use a trigonometric ratio (sine, cosine, or tangent) to solve for one of the other side lengths. For full credit, please provide both the ratio and work used to solve for the missing side length. Round your solution to the nearest hundredth.
The first part is pretty straight-forward. You can basically pick any angle measure and give an arbitrary length to any of the sides. So, give us something to work with. Pick an angle measure and a side (along with a side length).
Idk you choose
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\[\sin 68=\frac{ 17 }{ x }\] \[xsin68=17\] \[x=\frac{ 17 }{ \sin 68}\]
x in this case is the hypotenuse. Again, no calculator. You'll have to plug that in.
ok thanks :P
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