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If f(x) = 3x + 1, then f(a + h) - f(a) =
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To find \(f(a+h)\) rewrite \(f(x)\) substituting \((a+h)\) wherever you encounter \(x\). Do the same with \(f(a)\) and combine the expressions. Be careful to subtract polynomials properly!
could you work it out step by step? @whpalmer4
Of course. \[f(x)=3x+1\]This is our "pattern" \[f(a) = 3(a)+1\]That is \(f(a)\) — I just replaced \(x\) with \(a\) wherever I saw it Can you try \(f(a+h)\) for me?
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