Question

sin2x - 14 sin x + 2 = -5

Answer 1

solve for x?

Answer 2

solve for sin x

Answer 3

is the first term \[\sin^2x\]

Answer 4

yes sorry my bad

Answer 5

i call this a batman quadratic. 'a quadratic in disguise'

Answer 6

\[\large \sin^2 (x) -14 \sin x +2 =-5 \] think about \[\large ax^2 +bx+ c= 0\] and solve it like a quadratic.

Answer 7

Find all solutions to the equation.

would it be sin x=1?

Answer 8

lol chris.

Answer 9

thats wat mi teacher used to say

Answer 10

Or maaybe you can solve it by completing the square?

Answer 11

ohhh snhnap i forgot to add the 7

Answer 12

7 sin^2x - 14 sin x + 2 = -5

Answer 13

?...

Answer 14

sorry -.-

Answer 15

\[\large \ 7\sin^2 (x) -14 \sin x +2 =-5\]

Answer 16

that would make sense. thats easier.

Answer 17

add 5 to both sides then divide 7 to both sides.

Answer 18

sin^2(x)-2sinx+1
sinx(sinx-1)?

Answer 19

i feel like jhannybean is going to solve this nicely.

Answer 20

Yeah...we can solve it utilizing the quadratic equation. first,move the -5 to the other side. \[\large \ \frac{7\sin^2 (x)}{7} -\frac{14 \sin( x)}{7} +\frac{7}{7} =0\]\[\large \sin^2(x) -2\sin(x)+1=0\] quadratic formula. \[\large x= \frac{-(-2) \pm \sqrt{(-2)^2 -4(1)(1)}}{2}\]\[\large x= \frac{2}{2} = 1\]

Answer 21

Oh did i forget something...

Answer 22

sinx=1?

Answer 23

How would you solve this, chris?

Answer 24

kk.

Answer 25

Yes i believe im solving it the right way, lol.

Answer 26

we already know

where X=sinx