what is the area in square milimeters of a right trangle with a hypotenuse of 68 miilmeters and a leg of 60 milimeters?
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OpenStudy (jack1):
area = 1/2 base x ht
OpenStudy (jack1):
use pythagorus theorum to find height
OpenStudy (jack1):
u understand pythag theorum...?@linamireles16
OpenStudy (anonymous):
no still dont understand
OpenStudy (jack1):
ok, no worries
you have a right angled triangle, so you're able to use the formula:
\[h^2 = a^2 + b^2\]
where h = hypotenuse
a = ht
b = base
|dw:1371564419538:dw|
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OpenStudy (jack1):
so use h = 68 and b = 60 in the above formula to find a
OpenStudy (jack1):
then use a nd b in:
area = 1/2 base x ht
to find answer
OpenStudy (jack1):
so how'd you go for a?
OpenStudy (anonymous):
idid it wrong
OpenStudy (anonymous):
i got 1024
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OpenStudy (jack1):
ok... what did u do?
OpenStudy (anonymous):
for b
OpenStudy (jack1):
thats fine, a^2 = 1024, so what does a = ??
OpenStudy (anonymous):
4624=3600+bsquares
OpenStudy (anonymous):
sqare rooredd it and got 36 which is not a valid answer
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OpenStudy (jack1):
nah, sqrt 1024 = 32 hey
OpenStudy (anonymous):
yea you know what i mean ah
any how all my answers are 0000 options
OpenStudy (anonymous):
to the thousand
OpenStudy (jack1):
that's cool, you now have a and b, so find area
area of triangle = 1/2 x a x b
OpenStudy (jack1):
a = 32
b = 60
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OpenStudy (anonymous):
my aswer choices are 2,040
1,920
1,088
960
OpenStudy (jack1):
area of triangle = 1/2 x a x b
a = 32
b = 60
u tell me which is right dude?
OpenStudy (jack1):
\[area = (a \times b) / 2\]
OpenStudy (anonymous):
so its 32x60/2?
OpenStudy (jack1):
yep
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OpenStudy (anonymous):
thanks i got it
OpenStudy (anonymous):
what about 65 meters and leg of 25 meters?
OpenStudy (jack1):
sweet, welcome
OpenStudy (jack1):
as for 2nd q, do the same thing
find the verticle height and base length
use that to calculate area
OpenStudy (anonymous):
is it 750?
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OpenStudy (jack1):
so if you have right angle triangle, one side = base length
one side = verticle height
OpenStudy (jack1):
depends if 65 is hypotenuse or verticle height...?
OpenStudy (anonymous):
hypotenuse
OpenStudy (jack1):
cool, so what was vertical height length then...?
OpenStudy (anonymous):
idk i just guest
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OpenStudy (jack1):
ok... might work but probly not the best approach hey
OpenStudy (anonymous):
i got it right
OpenStudy (jack1):
noice! good guess dude
OpenStudy (anonymous):
anway whats the approxitmate side lenght of a square with a diagram of 16