Question

What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?



y= -2y= -3x+ 7
2x+ 3y- 7 = 0

Answer 1

first find the slope

Answer 2

idk the slope

Answer 3

do you have the formula?

Answer 4

no my teacher didnt give 1

Answer 5

y2 - y1
m = ---------
x2 - x1

Answer 6

x1,y1 x2,y2
you have points (3,-1) and (-1,5)

Answer 7

ok

Answer 8

m = (y2 - y1) / (x2 - x1)......m is the slope....set 1 (3,-1)...set 2 (-1,5)
m = (5 - (-1) / (-1 - 3)
m = 6/-4 = - 3/2
the slope is - 3/2

y = mx + b <--slope intercept form
we will be using slope - 3/2 and points (3,-1)
-1 = -3/2(3) + b
-1 = - 9/2 + b
-1 + 9/2 = b
-2/2 + 9/2 = b
7/2 = b

y = -3/2x + 7/2 <--this is your equation in slope intercept form.