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Mathematics 20 Online
OpenStudy (anonymous):

Factor completely: 3x^2 + 5x + 1 @Mertsj

OpenStudy (uri):

Quadratic formula is :(-b ± √(b² ‒ 4ac)]/(2a) a =3 b =5 c =1

OpenStudy (anonymous):

u can always use this formula for solving such equations: ax^2+bx+c=0 then roots are x=[-b+Squrt(b^2-4ac)]/2a & [-b-sqrt(b^2-4ac)]/2a Here a=3 , b=5 & c=1 Try it now

OpenStudy (uri):

You can do it now :D i said the same @Anu2401

OpenStudy (anonymous):

Ya both posted simultaneously .. But u were first :)

OpenStudy (uri):

Haha yea :)

OpenStudy (anonymous):

@johnweldon1993

OpenStudy (anonymous):

@Mertsj Can you set up the quadratic form for this. > . < I get mixed up when I try to.

OpenStudy (mertsj):

Yes. Since it won't factor by the usual methods, you use the quadratic formula to find the roots. Do that and then I will help you write the factors.

OpenStudy (anonymous):

I was asking you how to set up the quadratic formula. > . < It confuses me.

OpenStudy (mertsj):

oh. ok

OpenStudy (mertsj):

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