thanks @julian25
could you explain me one more question of similar type?
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OpenStudy (anonymous):
post it
OpenStudy (anonymous):
How many words are possible using the letters in the word *APPLE*. If the letters may not be repeated.
OpenStudy (anonymous):
for the fisrt position of the word u have 5 posibles leters to chose from
for the second position of the word u could chose 4 leters an so on
so u get 5! =5*4*3*2*1
OpenStudy (anonymous):
no, but there are two P's and they should not be repeated, if i do it your way i won't be applying the condition above.
OpenStudy (anonymous):
u r right 5! is if u could repeating leters
5!/2! is if the leter may not be repeated
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OpenStudy (anonymous):
so the logic behind it is same as for the first question? here also we are using the property of distinguishable permutation?