Question

curves: 1) x^2 + xy + y^2 = 1
2) x^2-xy+y^2=1

find dy/dx for each of the curves.
can someone go with me point by point of how to solve it? i am stuck on xy and don't know what exactly its derivative, is it 1dy/dx or just 1.

Answer 1

$$\frac{d}{dx}[xy]=y\frac{d}{dx}x+x\frac{d}{dx}y=y+xy'$$

Answer 2

thank you, can you tell me how we got to this: \[1) \frac{ dy }{ dx } = \frac{ -2x+y }{ x+2y } \]
\[2) \frac{ dy }{ dx } =\frac{ -2x+y }{ -x+2y }\]