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Can someone help me solve the inverse of f(x)=2x/(x-2). This is what I have. y=2x/(x-2). Then x=2y/(y-2). Then x+2 =2y/y. But what do I do next?? I'm stuck. Please help
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solve \(x=\frac{2y}{y-2}\) for \(y\)
first step is to multiply by \(y-2\) to get rid of the annoying denominator and write \[x(y-2)=2y\] second step is to multiply out on the left to get \[xy-2x=2y\] can you take it from there?
Thank you. You really helped. :)
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