Question

Can someone help me solve the inverse of f(x)=2x/(x-2). This is what I have. y=2x/(x-2). Then x=2y/(y-2). Then x+2 =2y/y. But what do I do next?? I'm stuck. Please help

Answer 1

solve \(x=\frac{2y}{y-2}\) for \(y\)

Answer 2

first step is to multiply by \(y-2\) to get rid of the annoying denominator and write
\[x(y-2)=2y\]
second step is to multiply out on the left to get
\[xy-2x=2y\]
can you take it from there?

Answer 3

Thank you. You really helped. :)