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i know i have to substitute x from 82 but the power on both side is the problem @SharpEdge
can u show the work pls
hmm its 82 not 81
k
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raise to the power of sqrt x on both sides, so that you are only left with f(x^2+1) on left, right side = \(\large x^{\dfrac{6\sqrt x}{x}}=x^{\dfrac{6}{\sqrt x}}\) now to get , f(82) , from f(x^2+1), just plug in x=9
so, \(\huge f(9^2+1)=f(82)=9^{\dfrac{6}{\sqrt9}}=...?\) simplify.....
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