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Mathematics 12 Online
OpenStudy (anonymous):

solve log3x+log9=0

OpenStudy (whpalmer4):

Adding logs is like taking the log of the product. Assuming your equation is \[\log 3x + \log 9 = 0\] (and not something involving a log base 3!) that is the same as writing \[\log 9*3x = 0\] or \[\log 27x = 0\]Take the anti-log of both sides and solve for \(x\).

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