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Find the equation, in standard form, of the line passing through the points (5,1) and (-2,3).
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with those points you could find the slope
how?
y2-y1 over x2-x1
oh ok and then use y=mx+b
yes, you can use that equation to get standard form but you know how?
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i think so... the slope would be -2/7 then you put that into the m spot of the y=mx+b form right?
yes and pick a point and plug it in the x and y to solve for b then change it into standard form
ok cool so it would be y=-2/7-17/7?
how would you write this in standard form?
maybe one of us did something wrong. I got in slope intercept y = -1/5x + 17
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i keep getting 2/7 as the slope
which points are you using?
5,1 and -2,3
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