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For the geometric sequence of a1=2 and r=2 find a5
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@mathisfun13 Have you studies Geometric Sequences?
yea
OK, it's of the form \[a_0, a_1, a_2...\] in terms of \(a_0\) \[a_1=a_0 \times r\] \[a_2=a_0\times r^2\] for any \(a_n\) \[a_n=a_0\times r^{n-1}\] r=common ratio Do you get this part?
yesss
what would the n be tho? cause i dont see a n in the problem
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For our case , we need to find a5 so n=5. Can you find a0 from a2 and given r
i thinkk so
Good, let me know if you get stuck
oooh i got 32?
Sorry, here a1 is actually a0. So it's a straight forward problem \[a_5=a_1r^{5-1}\] \[a_5=a_1r^4\] You are right :) \[a_5=2 \times 2^4=32\]
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