Question

.Solve: log (2x + 1) = log (x - 1).

Answer 1

exponentiate both sides

Answer 2

\[\begin{align}\log (2x + 1) &= \log (x - 1)\\e^{\log (2x + 1) }&= e^{\log (x - 1)}\\2x+1&=x-1\end{align}\]

Answer 3

then you solve for x?

Answer 4

yeah, what do you get?

Answer 5

x=-2

Answer 6

if you would like to check your solution

\[\begin{align}\log (2(-2) + 1) &= \log ((-2) - 1)\\\log(-3)&=\log(-3)\end{align}\]

which is always true

Answer 7

so you have found the solution for x