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Find an equation for the nth term of a geometric sequence where the second and fifth terms are -2 and 16, respectively.
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@Loser66
@amistre64 @hartnn
nth term = a1* r^(n-1) so 5th term = a1*r^4 and 2nd term = a1*r this should help r = common ratio which is the value you multiply each term to get the next term
Is it an = 1 * (-2)^n-1?
r^3 = 16 / -2 = -8 so r = -2
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so a1 = -2/-2 = 1
a1 must = 1, r = -2 then 1*(-2)^n-1, thanks man!
you r right
yw - actually i'm a woman
Oh lol ok, won't happen again :)
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maybe a write like a man! - that's ok
Nononono! I wasnt saying that lol!! The internet is tricky sometimes! :P
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