I have noo idea how to do these ):

What is the quotient?

http://roads.advancedacademics.com/coursecontent/math/IIB05/AlgIIB_unit1a_files/image103.jpg

A. 3x^3 - 10x^2 + 14x - 7
B. 3x^4 - 10x^3 + 14x^2 - 7
C. 3x^3 - 4x^2 +6x - 5
D. 3x^2 - 4x + 6

Question

I have noo idea how to do these ):

What is the quotient? 

http://roads.advancedacademics.com/coursecontent/math/IIB05/AlgIIB_unit1a_files/image103.jpg

A. 3x^3 - 10x^2 + 14x - 7
B. 3x^4 - 10x^3 + 14x^2 - 7
C. 3x^3 - 4x^2 +6x - 5
D. 3x^2 - 4x + 6

anonymous · Answer

this is part of a synthetic division problem right?

anonymous · Answer

the dividend is $3x^3-10x^2+14x-7$, the divisor is $x-2$ 
the quotient is $3x^2-4x+6$ and the remainder is $5$

anonymous · Answer

well its polynomial division, but the answer is D then? ... i guess i just dont understand how these work.  =/

anonymous · Answer

this is a weird way to present synthetic division
kind of backwards
if you wanted to divide 
$$(3x^3-10x^2+14x-7)\div (x-2)$$  you would set it up as you see above
the bottom line is the quotient and the remainder is 5

anonymous · Answer

the blue lines are so confusing to me, i didnt know what to do with that random 5! that makes a little more sense though, thank you for typing ut out and explaining it!