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Mathematics 16 Online
OpenStudy (anonymous):

Can anyone explain how to solve this?

OpenStudy (anonymous):

OpenStudy (jack1):

heya RH so your graph "B" refers to the 2nd equation ( (x+2)/6 < x-3 ) if you change the < to an =, you can work out the value of x where LHS = RHS occurs at x=4 so your equation is true for values of x of 4 or greater whereas your graph "A" refers to the first equation ( 3x - 9 > (-3/2)x ) if you change the > to an =, you can work out the value of x where LHS = RHS occurs at x=2 so your equation is true for values of x of 2 or greater ...hope this helps

OpenStudy (anonymous):

@Jack1 thanks a lot! So A is the correct answer then?

OpenStudy (jack1):

yeah im not 100% dude as A fits eqn 1 and B fits eqn 2, so ... can they both be right...?

OpenStudy (anonymous):

I am not sure either :( I have to choose one though

OpenStudy (jack1):

in that case i'd go B as its true for both equations

OpenStudy (jack1):

ooo shiny, thanks1!

OpenStudy (anonymous):

Thanks!

OpenStudy (jack1):

so was it A or B? i kinda want to change my answer to A now as the questions says "OR": 3x - 9 > (-3/2)x OR (x+2)/6 < x-3 if it said AND, then the 2 would have to overlap, but OR means either, so you'd have a greater range with or.

OpenStudy (anonymous):

So you think A would be the correct answer?

OpenStudy (jack1):

lock in A

OpenStudy (anonymous):

Thanks :)!

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