What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?

Question

ivettef365 · Answer

first what is the slope on the equation y = -3x + 1

anonymous · Answer

-3 @ivettef365

ivettef365 · Answer

good, now to be perpendicular it needs to be opposite reciprocal, so what would be the slope

anonymous · Answer

1/3 i think

ivettef365 · Answer

very good, now the only thing you need to find is the y-int to write the equation of the line

ivettef365 · Answer

so you have y = mx + b ( that is the equation of the line)
you have slope = 1/3
points; (-6,1), 
1 = 1/3(-6) + b   (can you find value of b)

anonymous · Answer

b=3. so would the equation be y = 1/3x + 3?

ivettef365 · Answer

good, so now you have m = 1/3 and b = 3
so the equation of the line is:
y = 1/3m+3

ivettef365 · Answer

sorry I meant 
y = 1/3x + 3

anonymous · Answer

okay thank you so much!! i might have more questions later on btw haha

ivettef365 · Answer

yw :)

anonymous · Answer

What is the equation of a horizontal line passing through the point (–7, 5)