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Mathematics 16 Online
OpenStudy (anonymous):

@jim_thompson5910 @mathslover

mathslover (mathslover):

Pair of rectangles? But, there is only a single rectangle in the figure...

OpenStudy (anonymous):

soryy

OpenStudy (anonymous):

is this in a proportion?

mathslover (mathslover):

The ratios shall be same here . Let For first rectangle : 100 = \(L_1\) 40 \(H_1\) and For second rectangle : 40 = \(L_2\) x = \(H_2\) Then : \(\cfrac{L_1}{L_2} = \cfrac{H_1}{H_2}\)

mathslover (mathslover):

Plug - in the values for \(L_1,~ L_2 , ~ H_1 , ~ H_2 \) and then solve for x.

mathslover (mathslover):

Can you do that @divagirl421 ?

OpenStudy (anonymous):

yes ill try

mathslover (mathslover):

Good. Let me know what you get.

OpenStudy (anonymous):

16

mathslover (mathslover):

Right :) ...

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