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What is the standard form equation of the line passing through (3, -2) with a slope of 3 over 5?
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a) 5x - 3y = 19 b) 5x - 3y = -19 c) 3x - 5y = 19 d) 3x - 5y = -19
m=3/5 (3,-2) Y=mx+c ...sub into this equation
-2= 3/5(3)+c
like this?
yep then find c once you have found c...multiply by 5 throughout
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idk how to do it... i got the equation but idk how to solve
y=3/5 X-19/5 5Y= 3/5 (5) X- 19/5 (5)
i dont know how to multiply with the fraction.
formula needed for it\[y-y _{1}=m(x-x _{1})\]
@danny562 3/5 X 5/1 ...like that u cancel the 5
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given\[x _{1}=3,y _{1}=-2,m=\frac{ 3 }{ 5 }\]
so the equation of line will b\[y-(-2)=\frac{ 3 }{ 5 }(x-3)\]
so the answer is c
ya
3x-5y=19
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ya
@danny562 yes....yay!!
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