Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

Answer 1

ok i wanna try it

Answer 2

u hv a line\[y=-3x+7\]

Answer 3

the slope of ur given line is\[m _{1}=-3\]

Answer 4

did u get it

Answer 5

if the slope of ur perpendicular line is \[m _{2}\]

Answer 6

then the law is\[m _{1}m _{2}=-1\]

Answer 7

\[(-3)m _{2}=-1\]

Answer 8

\[m _{2}=\frac{ 1 }{ 3 }\]

Answer 9

so the equation of ur perpendicular line will b \[y-(-1)=\frac{ 1 }{ 3 }(x+6)\]

Answer 10

solve it

Answer 11

formulae (y-y1)=-1/m(x-x1)

substitute

Answer 12

m=-3
(x1,y1)=(6,-1)

Answer 13

did u get it

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