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Mathematics 10 Online
OpenStudy (anonymous):

Find the limit of the function by using direct substitution. x-> lim(x^2 + 8x - 2)

OpenStudy (jhannybean):

what is x tending to?0?

OpenStudy (anonymous):

2

OpenStudy (jhannybean):

ok.

OpenStudy (jhannybean):

substitute 2 into your limit to find the limit.

OpenStudy (anonymous):

18 Does not exist 0 -18

OpenStudy (jhannybean):

\[\large (2)^2+8(2)-2\]?

OpenStudy (anonymous):

4 + 16 - 2 = 18

OpenStudy (anonymous):

ohhh! Thank you!

OpenStudy (anonymous):

Jhannybean what about this:

OpenStudy (anonymous):

x->2 (x^2-4)/(x-2) Does not exist because its 0/0 right?

OpenStudy (jhannybean):

yes, 2 is where your function does not exist.

OpenStudy (primeralph):

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