/_\ DEF has vertices D(-2,4), E(0,-2), and F(6,2). Determine:
a) an equation for DG, the median from D to EF
b) an equation for FC, the altitude from F to DE
c) an equation for AB, the right bisector of DF
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jimthompson5910 (jim_thompson5910):
point G is the midpoint of segment EF
so you use the midpoint formula to find point G
jimthompson5910 (jim_thompson5910):
what do you get when you do that
OpenStudy (anonymous):
Point G is (3,0)
OpenStudy (anonymous):
Then i found the slope of the of DG which is -4/5
jimthompson5910 (jim_thompson5910):
so far, so good
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jimthompson5910 (jim_thompson5910):
what's next?
OpenStudy (anonymous):
Im not sure
jimthompson5910 (jim_thompson5910):
well you know the slope -4/5
jimthompson5910 (jim_thompson5910):
you know a point that this line goes through (-2,4)
OpenStudy (anonymous):
the final answer is 4x+5y-12=0
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jimthompson5910 (jim_thompson5910):
so
y = mx + b
y = (-4/5)x + b
4 = (-4/5)(-2) + b
4 = 8/5 + b
4 - 8/5 = b
b = 12/5
OpenStudy (anonymous):
so do i put it into y=mx+b?
jimthompson5910 (jim_thompson5910):
the equation in slope intercept form is y = (-4/5)x + 12/5
jimthompson5910 (jim_thompson5910):
if you want the equation in standard form, you would get
y = (-4/5)x + 12/5
5y = -4x + 12
4x + 5y = 12
OpenStudy (anonymous):
thanks alot!!!!!!!
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